pta-2024年秋面向对象程序设计实验一-java

文章申明:作者也为初学者,解答仅供参考,不一定是最优解;

一:7-1 sdut-sel-2 汽车超速罚款(选择结构)

答案:

import java.util.Scanner;

        public class Main {

public static void main(String[] arg){

        Scanner sc=new Scanner(System.in);

        int a=sc.nextInt();

        int b=sc.nextInt();

        int c=b-a;

        if(c>=1&&c<=20) {

        System.out.println("You are speeding and your fine is 100.");

                }         

        else if(c>=21&&c<=30){

        System.out.println("You are speeding and your fine is 270.");

                }

        else if(c>=31)System.out.println("You are speeding and your fine is 500.");

        else System.out.println("Congratulations, you are within the speed limit!");

}

}

 

二: 7-2 Java中二进制位运算

答案:

import java.util.Scanner;

public class Main{

        public static void main(String[] args){

        Scanner sc=new Scanner(System.in);

        int a=sc.nextInt();

        String c=sc.next();

        int b=sc.nextInt();

        switch(c){

        case "&":

        System.out.println(a+" & "+b+" = "+(a&b));

        break;

        case "|":

        System.out.println(a+" | "+b+" = "+(a|b));

        break;

        case "^":

        System.out.println(a+" ^ "+b+" = "+(a^b));

        break;

        default:

        System.out.println("ERROR");

        break;

                }

        }

}

 

三:7-3 sdut-最大公约数和最小公倍数 

 答案:

import java.util.Scanner;

public class Main{

        public static void main(String[] args){

                Scanner sc=new Scanner(System.in);

                  while(sc.hasNext()){

                        int a=sc.nextInt();

                        int b=sc.nextInt();

                        System.out.print(ans(a,b));

                        System.out.print(" "+a*b/ans(a,b));

                        System.out.println();

                                                        }

                                        }

public static int ans( int a, int b){

                if(b>a){

                        int tem=a;

                        a=b;

                        b=tem;

                     

评论 1
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值