合并检测(蓝桥杯20C)

#include<stdio.h>
const float n = 10002.0f;
int main() {
	int k;
	float p = 0.01;
	float sum;
	float min = 1000000;
	int mink;
	for (k = 1; k <= 100;k++) {
		sum = n / k + n * k * p;
		//(1/(p*k)+k)*(n/(1/p))
		if (sum < min) {
			min = sum;
			mink = k;
		}
	}
	printf("%d",mink);
}