【LeetCode | 数据库】订单最多的客户

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题目

表: Orders

+-----------------+----------+
| Column Name     | Type     |
+-----------------+----------+
| order_number    | int      |
| customer_number | int      |
+-----------------+----------+
在 SQL 中，Order_number是该表的主键。
此表包含关于订单ID和客户ID的信息。
 

查找下了 最多订单 的客户的 customer_number 。

测试用例生成后， 恰好有一个客户 比任何其他客户下了更多的订单。

查询结果格式如下所示。

 

示例 1:

输入: 
Orders 表:
+--------------+-----------------+
| order_number | customer_number |
+--------------+-----------------+
| 1            | 1               |
| 2            | 2               |
| 3            | 3               |
| 4            | 3               |
+--------------+-----------------+
输出: 
+-----------------+
| customer_number |
+-----------------+
| 3               |
+-----------------+
解释: 
customer_number 为 '3' 的顾客有两个订单，比顾客 '1' 或者 '2' 都要多，因为他们只有一个订单。
所以结果是该顾客的 customer_number ，也就是 3 。
 

进阶： 如果有多位顾客订单数并列最多，你能找到他们所有的 customer_number 吗？

代码

SELECT customer_number
FROM Orders
GROUP BY customer_number
HAVING COUNT(order_number) = (
    SELECT MAX(order_count)
    FROM (
        SELECT COUNT(order_number) AS order_count
        FROM Orders
        GROUP BY customer_number
    ) AS counts
);