式子好难推。。看别人的博客好了。。
#include <bits/stdc++.h>
using namespace std;
#define N 10000005
#define P 20101009
bool vis[N];
int prime[N],miu[N];
typedef long long LL;
LL x[N], ans;
int cnt,n,m;
void Miu()
{
cnt = 0;
miu[1] = 1;
x[1] = 1;
for (int i=2;i<=N-5;i++)
{
if (!vis[i])
{
prime[++cnt] = i;
miu[i] = -1;
x[i] = ((LL)(1 - i) % P + P) % P;
}
for (int j=1;j<=cnt && prime[j] * i <= N-5;j++)
{
vis[i * prime[j]] = 1;
if (i % prime[j] == 0)
{
x[i * prime[j]] = x[i];
break;
}
else
{
miu[i * prime[j]] = -miu[i];
x[i * prime[j]] = x[i] * x[prime[j]] % P;
}
}
}
for (int i=1;i<=N-5;i++)
x[i] = (x[i-1] + x[i] * (LL)i % P) % P;
}
int main()
{
Miu();
scanf("%d%d", &n, &m);
if (n > m) swap(n,m);
ans = 0;
for (int l = 1,r;l<=n;l = r+1)
{
r = min(n / (n / l), m / (m / l));
ans = (ans + 1LL * (1 + n / l) * (n / l) % P * (1 + m / l) % P * (m / l) % P * (x[r] - x[l-1] + P) % P) % P;
}
ans = (ans * 15075757) % P;
printf("%lld\n", ans);
}