UVA - 621 Secret Research

最新推荐文章于 2017-09-06 14:55:20 发布

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本文介绍了一种用于解析特定实验室中秘密研究结果的程序。通过分析一系列由数字组成的字符串，该程序能够确定实验是否成功、失败、未完成或为负结果。通过对输入序列的判断，输出相应的结果标记，如'+', '-', '?' 或 '*'。

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At a certain laboratory results of secret research are thoroughly encrypted. A result of a single experiment is stored as an information of its completion:

`positive result', `negative result', `experiment failed' or `experiment not completed'

The encrypted result constitutes a string of digits S, which may take one of the following forms:

 positive result 		 S = 1 or S = 4 or S = 78  negative result 		 S = S35  experiment failed 		 S = 9S4  experiment not completed 		 S = 190S

(A sample result S35 means that if we add digits 35 from the right hand side to a digit sequence then we shall get the digit sequence corresponding to a failed experiment)

You are to write a program which decrypts given sequences of digits.

Input

A integer n stating the number of encrypted results and then consecutive n lines, each containing a sequence of digits given as ASCII strings.

Output

For each analysed sequence of digits the following lines should be sent to output (in separate lines):

+ for a positive result - for a negative result * for a failed experiment ? for a not completed experiment

In case the analysed string does not determine the experiment result, a first match from the above list should be outputted.

Sample Input

Sample Output

+
-
?
*
题意
按照题目中的要求顺序判断四种情况，按照符合条件各自输出；


#include<stdio.h>
#include<string.h>
#include<iostream>
#define llu long long unsigned;
using namespace std;

int main()
{
	int n;
	string k;;
	cin >> n;
	getchar();
		for(int i = 0;i < n; i ++)
		{
			cin >> k;
			int m = k.length();
			if( m == 1)
			{
				if(k[0] == '1' || k[1] == '4')
					cout <<"+"<<endl;
			
			}

			else if(m ==2)
			{
				if(k[0] == '7' && k[1] == '8')
					cout <<"+"<<endl;
			
			
			}
			else
			{
				if(k[m - 2] == '3'&& k[m- 1] == '5')
					cout <<"-"<<endl;
				else if(k[0] =='9'&& k[m - 1]== '4')
					cout <<"*"<<endl;
				else
					cout <<"?"<<endl;
			
			}
		}
return 0;
}