去通易笔试时的编程题目

//输入一个字符串，判断其是否移动电话号码：

//条件1：长度为13

//条件2：为数字

// 条件3：开头是86<wbr></wbr>

//条件依次按顺序判断 <wbr></wbr> <wbr><wbr></wbr></wbr>

private static int judgeMoble(String mobile){

char[] each = mobile.toCharArray();

if (each.length != 13) {

System.out.println("长度不为13");

return 1;

}

boolean flag = true;

for (int i = 0; i < each.length && flag; i++) {

if(!Character.isDigit(each[i])){

System.out.println("each:" + each[i]);

System.out.println("非数字");

flag = false;

return 2;

}

}

String top = String.valueOf(each[0]) + String.valueOf(each[1]);

System.out.println("top:"+top);

if (!top.equals("86")) {

System.out.println("开头不是86");

return 3;

}

return 0;

}

//调试省略