C实现顺序栈和链式栈
看到《剑指offer》面试题7,用两个栈实现队列这道题,所以就分别把栈和队列都实现了一下,栈和队列都有两种存储方式,一种是顺序存储,另外一种是链式存储。
栈,有栈顶指针指向当前栈最顶的元素。顺序栈,则栈中的元素用数组保存即可;链式栈,关键是如何通过链表把栈中的元素串起来,栈顶指针top指向当前栈中的栈顶元素,有新的元素入栈时,新的元素的next指向栈顶元素,同时栈顶指针指向新的元素。
顺序栈代码如下:
#include <stdio.h>
#include <malloc.h>
#define max_size 50
typedef struct Stack {
int arr[max_size];
int top;
}stack;
stack *create()
{
stack *stk = (stack *)malloc(sizeof(stack));
stk->top = -1;
return stk;
}
void push(stack *s, int val)
{
s->top ++;
s->arr[s->top] = val;
}
void pop(stack *s, int *val)
{
*val = s->arr[s->top];
s->top --;
}
void destroy(stack *s)
{
free(s);
}
int main()
{
stack *stk; /* 定义一个指针变量,分配的内存空间大小是指针占的内存空间大小,不是指针指向的数据类型的空间 */
//stk = (stack *)malloc(sizeof(stack));
stk = create();
int a = 1, b = 2;
int c;
push(stk, a);
push(stk, b);
while (stk->top >= 0) {
int tmp = stk->top;
printf("%d\n", stk->arr[tmp]);
pop(stk, &c);
}
destroy(stk);
return 0;
}
链式栈的代码:
#include <stdio.h>
#include <malloc.h>
typedef struct LNode {
int val;
struct LNode *next;
}node;
typedef struct Stack {
node *top;
int size;
}stack;
stack *create()
{
stack *stk = (stack *)malloc(sizeof(stack));
stk->size = 0;
stk->top = NULL;
return stk;
}void push(stack *s, int val)
{
node *p = (node *)malloc(sizeof(node));
p->val = val;
p->next = s->top;
s->top = p;
++ s->size;
}
void pop(stack *s, int *val)
{
node *tmp = s->top;
*val = s->top->val;
s->top = s->top->next;
-- s->size;
free(tmp);
}
void destroy(stack *s)
{
if (!s->size) {
free(s);
}
}
int main()
{
stack *stk;
//stk = (stack *)malloc(sizeof(stack));
stk = create();
int a = 1, b = 2;
int c;
push(stk, a);
push(stk, b);
while (stk->size > 0) {
printf("%d\n", stk->top->val);
pop(stk, &c);
}
destroy(stk);
return 0;
}