根据设备定位所得的经纬度，获得具体的地址

最新推荐文章于 2021-05-26 16:57:22 发布

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最新推荐文章于 2021-05-26 16:57:22 发布

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分类专栏： Android技术文章标签： android string null output url io

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关于android2.2地图定位的问题，程序员取得了设备所在经纬度，得不到具体的地址。这里做一下总结。转自：http://blog.youkuaiyun.com/sun6223508/archive/2011/06/21/6559384.aspx

在android2.1上面这段代码可以通过经纬度取得设备（或者说用户）所在的具体位置，而且很快。

但是在android2.2上面这段代码每次执行都是报IO异常的,通过经纬度得不到具体位置。这是因为上面这段代码在android2.2是一个BUG。

解决办法就是在异常处理的时候加上一个方法getaddressLocation(double lat, double lon, int maxResults) ；异常代码如下。

public static List<Address> getaddressLocation(double lat, double lon, int maxResults) {
	        String url = "http://maps.google.com/maps/geo?q=" + lat + "," + lon + "&output=json&sensor=false";
	                String response = "";
	                List<Address> results = new ArrayList<Address>();
	                HttpClient client = new DefaultHttpClient();
	                
	                try {
	                        HttpResponse hr = client.execute(new HttpGet(url));
	                        HttpEntity entity = hr.getEntity();
	                        BufferedReader br = new BufferedReader(new InputStreamReader(entity.getContent()));
	                        String buff = null;
	                        while ((buff = br.readLine()) != null)
	                                response += buff;
	                } catch (IOException e) {
	                        e.printStackTrace();
	                }
	                JSONArray responseArray = null;
	                try {
	                        JSONObject jsonObject = new JSONObject(response);
	                        responseArray = jsonObject.getJSONArray("Placemark");
	                } catch (JSONException e) {
	                        return results;
	                }
	                
	                for(int i = 0; i < responseArray.length() && i < maxResults-1; i++) {
	                        Address addy = new Address(Locale.getDefault());
	                        try {
	                                JSONObject jsl = responseArray.getJSONObject(i);
	                                String addressLine = jsl.getString("address");
	                                if(addressLine.contains(","))
	                                        addressLine = addressLine.split(",")[0];
	                                addy.setAddressLine(0, addressLine);
	                                jsl = jsl.getJSONObject("AddressDetails").getJSONObject("Country");
	                                addy.setCountryName(jsl.getString("CountryName"));
	                                addy.setCountryCode(jsl.getString("CountryNameCode"));
	                                jsl = jsl.getJSONObject("AdministrativeArea");
	                                addy.setAdminArea(jsl.getString("AdministrativeAreaName"));
                     jsl = jsl.getJSONObject("Locality");
	                                addy.setLocality(jsl.getString("LocalityName"));
	                                addy.setThoroughfare(jsl.getJSONObject("Thoroughfare").getString("ThoroughfareName"));
	                        } catch (JSONException e) {
	                                e.printStackTrace();
	                                continue;
	                        }
	                        results.add(addy);
	                }
	                return results;
	        }