一、实现一个基于链表法解决冲突问题的散列表
class MyDict:
def __init__(self, num=100): # 指定列表大小
self._num = num
self._lst = []
for _ in range(self._num):
self._lst.append([])
def update(self, key, value): # 添加 key-value
key_index = hash(key) % self._num
for i, (k, v) in enumerate(self._lst[key_index]):
if key == k:
self._lst[key_index][i] = [key, value]
break
else:
# 处理hash冲突的关键
self._lst[key_index].append([key, value])
def get(self, key): # 根据指定的 key 弹出值
key_index = hash(key) % self._num
for k, v in self._lst[key_index]:
if k == key:
return v
else:
raise KeyError('No such {} key'.format(key))
def pop(self, key): # 根据 key 弹出元素 并且删除
key_index = hash(key) % self._num
for i, (k, v) in enumerate(self._lst[key_index]):
if k == key:
result = v
self._lst.pop(i)
return result
else:
raise KeyError('No such {} key'.format(key))
def __getitem__(self, key): # 可以通过下标来取值
key_index = hash(key) % self._num
for k, v in self._lst[key_index]:
if k == key:
return v
else:
raise KeyError('No such {} key'.format(key))
def keys(self): # 取得所有的key
for index in range(self._num):
for k, v in self._lst[index]:
yield k
def values(self): # 取得所有的 value
for index in range(self._num):
for k, v in self._lst[index]:
yield v
def items(self): # 取得所有的条目
for index in range(self._num):
for item in self._lst[index]:
yield item
二、实现一个 LRU 缓存淘汰算法
class LRUcache:
def __init__(self, size=3):
# 缓存大小固定为3
# keys 排名由顺序表示
self.cache = {}
self.keys = []
self.size = size
def get(self, key):
#取值
if key in self.cache:
self.keys.remove(key)
self.keys.insert(0, key)
return self.cache[key]
else:
return None
def set(self, key, value):
if key in self.cache:
self.keys.remove(key)
self.keys.insert(0, key)
self.cache[key] = value
elif len(self.keys) == self.size:
# 删除最老的元素
old = self.keys.pop()
self.cache.pop(old)
self.keys.insert(0, key)
self.cache[key] = value
else:
self.keys.insert(0, key)
self.cache[key] = value
if __name__ == '__main__':
test = LRUcache()
test.set('a',2)
test.set('b',2)
test.set('c',2)
test.set('d',2)
test.set('e',2)
print(test.get('c')) # 2
test.set('f',2)
print(test.get('b')) # None
print(test.get('a')) # None
print(test.get('e')) # 2 只保留了后3个e,c,f的值