关于jQuery中$.grep的筛选问题

对数组对象的筛选基本上和数组是一致的，是筛选为新的数组对象：

情况一：（数组中的每个对象都有f这个属性的话，可以简单地直接使用）

var arrjson=[

{"a":15,"b":"bbbbbbbbbbb","f":{"obj":222,"json":8000}},

{"a":16,"c":"234fewr","f":{"obj":6666,"json":8000}},

{"a":90,"d":"qweqwe","f":{"obj":6666,"json":8000}}

]

var wq=$.grep(arrjson, function(i) {

return i.f.obj==6666

});

console.log(wq)

情况二：（数组中并非所有对象都有指定的属性）

var arrjson=[

{"a":3,"b":"213123"},

{"a":32},

{"a":65},

{"a":12},

{"a":13},

{"a":14},

{"a":15,"b":"bbbbbbbbbbb","f":{"obj":222,"json":8000}},

{"a":16,"c":"234fewr","f":{"obj":6666,"json":8000}},

{"a":90,"d":"qweqwe","f":{"obj":6666,"json":8000}}

]

var ww=$.grep(arrjson,function(n){

return n.f;

})

var wq=$.grep(ww, function(i) {

return i.f.obj==6666

});

console.log(ww)