本题注意点:root.left, root.right = root.right, root.left
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def invertTree(self, root):
"""
:type root: TreeNode
:rtype: TreeNode
"""
if not root: return None
self.invertTree(root.left)
self.invertTree(root.right)
root.left, root.right = root.right, root.left
# version2: (我)
# temp = root.left
# root.left = root.right
# root.right = temp
return root
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