【CSS3】使用:not(:last-of-type)简化你的css代码

演示效果：第三个标题没有下边框

以前写代码是这样：

<style>
.posts {
  list-style: none;
  margin: 0;
  padding: 0;
}
.post {
  border-bottom: 1px solid #eee;
  margin-bottom: .5rem;
  padding-bottom: .5rem;
}
.post:last-child {
    border-bottom: 0;
    margin-bottom: 0;
    padding-bottom: 0;
}
</style>
<!-- This is what your html would look like -->
<ul class="posts">
  <li class="post">
    <a href="/link-to-post/" title="Permalink to post">
      <h2>Post Title</h2>
      <small>Thurs, Feb 16, 2017<small>
    </a>
  </li>
</ul>

现在是这样：

<style>
.posts {
  list-style: none;
  margin: 0;
  padding: 0;
}
.post:not(:last-of-type) {
  border-bottom: 1px solid #eee;
  margin-bottom: .5rem;
  padding-bottom: .5rem;
}
</style>
<!-- This is what your html would look like -->
<ul class="posts">
  <li class="post">
    <a href="/link-to-post/" title="Permalink to post">
      <h2>Post Title</h2>
      <small>Thurs, Feb 16, 2017<small>
    </a>
  </li>
</ul>

使用not(:last-of-type)，我们省掉了5行代码。