输入一个正数n，输出所有和为n连续正数序列

/*
输入一个正数n，输出所有和为n连续正数序列。
例如：输入15，由于1+2+3+4+5=4+5+6=7+8=15，所以输出3个连续序列1-5、4-6和7-8。

//*/

#include <iostream>
#include <iomanip>
#include <limits>
#include <cmath>
using namespace std;

int main(int argc, char** argv)
{
	if(argc < 2)
		return -1;
	int k = atoi(argv[1]);
	if(k%2){  // 奇数
		cout << "sum of { " << k/2 << " " << k/2 + 1 << " } is " << k << endl;
		for(int i = 3; i < k -1 ; i+=2){   // 对于任意偶数n(满足n>2)个连续整数相加，结果必为偶数
			if(!(k%i)){
				if( k/i - i/2 > 0){
					cout << "sum of { ";
					for(int idx = k/i - i/2; idx <= k/i + i/2; ++idx){					
						cout << idx << " ";
					}
					cout << "} is " << k << endl;
				}
			}
		}
	}else{
		for(int i = 3; i < k - 1; i += 1){
			if(!(k%i)){ // 奇数个连续整数和
				if( k/i - i/2 > 0){ 
					cout << "sum of { ";
					for(int idx = k/i - i/2; idx <= k/i + i/2; ++idx){
						cout << idx << " ";
					}
					cout << "} is " << k << endl;
				}
			}else if(!(i%2) && (k%i == i/2)){  // 偶数个连续整数和
				if( k/i - (i-1)/2 > 0){
					cout << "sum of { ";
					for(int idx = k/i - (i-1)/2; idx <= k/i + i/2; ++idx){
						cout << idx << " ";
					}
					cout << "} is " << k << endl;
				}			
			}
		}
	}
	return 0;
}