Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).
Example 1:
Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3.
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.
Example 2:
Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1.
class Solution {
public:
int findLengthOfLCIS(vector<int>& nums) {
if(nums.empty()) return 0;
int res = 1;
int tmp = 1;
for(int i = 1; i < nums.size(); i++){
if(nums[i] > nums[i - 1]){
tmp++;
} else {
res = max(tmp, res);
tmp = 1;
}
}
return max(res, tmp);
}
};