Oulipo
Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces. So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap. Input The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:
Output For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T. Sample Input 3 BAPC BAPC AZA AZAZAZA VERDI AVERDXIVYERDIAN Sample Output 1 3 0 Source |
[Submit] [Go Back] [Status] [Discuss]
题意:给n组数据,每组数据给出a串和b串,求b串在a串中共出现多少次
题解:KMP模版
贴上代码:
#include<cstdio>
#include<iostream>
#include<cstring>
#include<algorithm>
#define N 100010
using namespace std;
int nextval[N];
int lens,lenp;
char s[N*10],p[N];
void getnext()
{
int i = 0 , j = -1;
nextval[0] = -1;
while(i != lenp)
{
if(j == -1 || s[i] == s[j])
nextval[++i] = ++j;
else
j = nextval[j];
}
}
int KMP()
{
int i = 0 , j = 0 ,count = 0;
while(i != lens && j != lenp)
{
if(s[i] == p[j] || j == -1 )
++i,++j;
else
j = nextval[j];
if(j == lenp)
{
++count;
j = nextval[j];
}
}
return count;
}
int main()
{
int ncase,len,ans;
scanf("%d",&ncase);
while(ncase--)
{
scanf("%s%s",p,s);
lens = strlen(s);
lenp = strlen(p);
getnext();
ans = KMP();
printf("%d\n",ans);
}
}