Given a binary tree, flatten it to a linked list in-place.
For example,
Given
1
/ \
2 5
/ \ \
3 4 6
The flattened tree should look like:
1
\
2
\
3
\
4
\
5
\
6
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void flatten(TreeNode *root) {
while(root){
if(root -> left){
TreeNode *pre = root -> left;
while(pre -> right)
pre = pre -> right;
pre -> right = root -> right;
root -> right = root -> left;
root -> left = NULL;
}
root = root -> right;
}
}
};
本文深入探讨了如何通过迭代方式将二叉树结构转化为链表,具体步骤包括遍历左子树并更新指针指向,直至节点为空,确保链表的正确构建。
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