时间复杂度(O(n)),思想:细心,耐心
class Solution:
def rotate(self, matrix: [[int]]) -> None:
n = len(matrix)
for i in range(n // 2):
for j in range(i, n - i - 1):
curr_value = matrix[i][j]
for _ in range(4):
new_i, new_j = j, n - i - 1
curr_value, matrix[new_i][new_j], i, j \
= matrix[new_i][new_j], curr_value, new_i, new_j