Given a string containing just the characters '(', ')', '{', '}', '[' and ']',

本文介绍了一种使用Java栈实现的有效括号字符串验证方法。通过对输入字符串进行遍历,并利用栈来匹配成对出现的括号,最终判断字符串是否符合有效括号字符串的要求。

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首先我用的是java,java中提供了栈的包

class Solution {

   public boolean isValid(String s) {  

//定义一个栈

    Stack<String> stack = new Stack<String>();  

//通过分析,进行进栈处理

    for(int i=0;i<s.length();i++){  
        char c = s.charAt(i);  
        if(c=='{'||c=='['||c=='('){  
            stack.push(c);  
        }else{  
            if(stack.isEmpty()){  
                return false;  

            }  

//进行出栈判断

            if((c=='}' && stack.peek().equals("{"))||  
            (c==']' && stack.peek().equals("["))||  
            (c==')' && stack.peek().equals("("))){  
                stack.pop();  
            }else{  
                return false;  
            }  
        }  

    }  

//判断最后是否为空

    if(stack.isEmpty()){  
        return true;  
    }else{  
        return false;  
    }  
}  
}
We have come up with the best possible language here at Google, called Googlerese. To translate text into Googlerese, we take any message and replace each English letter with another English letter. This mapping is one-to-one and onto, which means that the same input letter always gets replaced with the same output letter, and different input letters always get replaced with different output letters. A letter may be replaced by itself. Spaces are left as-is. For example (and here is a hint!), our awesome translation algorithm includes the following three mappings: 'a' -> 'y', 'o' -> 'e', and 'z' -> 'q'. This means that "a zoo" will become "y qee". Googlerese is based on the best possible replacement mapping, and we will never change it. It will always be the same. In every test case. We will not tell you the rest of our mapping because that would make the problem too easy, but there are a few examples below that may help. Given some text in Googlerese, can you translate it to back to normal text? 输入 The first line of the input gives the number of test cases, T. T test cases follow, one per line. Each line consists of a string G in Googlerese, made up of one or more words containing the letters 'a' - 'z'. There will be exactly one space (' ') character between consecutive words and no spaces at the beginning or at the end of any line. 1 ≤ T ≤ 30. G contains at most 100 characters. None of the text is guaranteed to be valid English. 输出 For each test case, output one line containing "Case #X: S" where X is the case number and S is the string that becomes G in Googlerese. 样例 输入样例 1 复制 3 ejp mysljylc kd kxveddknmc re jsicpdrysi rbcpc ypc rtcsra dkh wyfrepkym veddknkmkrkcd de kr kd eoya kw aej tysr re ujdr lkgc jv 输出样例 1 Case #1: our language is impossible to understand Case #2: there are twenty six factorial possibilities Case #3: so it is okay if you want to just give up给出这个问题的思路,用C语言
06-11
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