如何读取kinect生成的图像序列

kinect图像序列名存储在文件 rgb.txt中，格式为

1305031102.175304 rgb/1305031102.175304.png
1305031102.211214 rgb/1305031102.211214.png
1305031102.243211 rgb/1305031102.243211.png
1305031102.275326 rgb/1305031102.275326.png
1305031102.311267 rgb/1305031102.311267.png
1305031102.343233 rgb/1305031102.343233.png
1305031102.375329 rgb/1305031102.375329.png
1305031102.411258 rgb/1305031102.411258.png
1305031102.443271 rgb/1305031102.443271.png
1305031102.475318 rgb/1305031102.475318.png
1305031102.511219 rgb/1305031102.511219.png
1305031102.543220 rgb/1305031102.543220.png
1305031102.575286 rgb/1305031102.575286.png
1305031102.611233 rgb/1305031102.611233.png
1305031102.643265 rgb/1305031102.643265.png

对应的图像存储路径为：D:\Matlab练习\rgbd_dataset_freiburg1_xyz\rgb
图像对应文件名为（以第一张图像为例）：1305031102.175304.png

目的：从rgb.txt中提取出rgb/1305031102.175304.png  ，使用imread()读取对应图像

步骤：
1、使用textread('rgb.txt',%s)读取文件内容

注：若不加 %s 则会出现如下错误
>> textread('rgb.txt')
??? Error using ==> dataread
Trouble reading number from file (row 1, field 2) ==> rgb/1305031102.175304.png\n

Error in ==> textread at 177
[varargout{1:nlhs}]=dataread('file',varargin{:});

读取：

      ss=textread('rgb.txt','%s');
      ss1=ss(2:2:200,1);
      s=ss1(k); %k：表示第k张图像

2、提取图像存储路径：
sequencePath = 'D:\Matlab练习\rgbd_dataset_freiburg1_xyz\';

3、连接存储路径和文件名
s1=strcat(sequencePath,s);

注：这里连接后的s1不能直接用于imread的输入，因为此时s1属于单元格形式，需要转换为字符串

直接用出现的错误
>> s1=strcat(sequencePath,s)

s1 =

    'D:\Matlab练习\rgbd_dataset_freiburg1_xyz\rgb/1305031102.175304.png'

>> imread(s1)
??? Conversion to logical from cell is not possible.

Error in ==> imread at 282
if (strfind(filename, '://'))

4、转换为字符串

im=char(s1);

5、读取序列图像

imread(im);

 

大功告成！