pyqt中快速创建一个简陋小键盘

最新推荐文章于 2022-12-29 14:28:33 发布

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最新推荐文章于 2022-12-29 14:28:33 发布

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文章标签： pyqt

本文链接：https://blog.youkuaiyun.com/zhong1213/article/details/115775260

版权

在这里插入图片描述

def constructKeypad(self):
        
        vlayout=QVBoxLayout()
        self.input=QLineEdit()
        vlayout.addWidget(self.input)
        hset=["1234567890","qwertyuiop","asdfghjkl","zxcvbnm"]
        for vset in hset:
            layout = QHBoxLayout()
            for i in vset:
                button = QPushButton(self)
                button.setText((i))
                button.clicked.connect(self.onKeyPad)
                layout.addWidget(button)
            vlayout.addLayout(layout)
        layout = QHBoxLayout()
        button = QPushButton(self)
        button.setText("确认")
        button.clicked.connect(self.onKeyPad)
        layout.addWidget(button)

        button = QPushButton(self)
        button.setText("删除")
        button.clicked.connect(self.onKeyPad)
        layout.addWidget(button)
        vlayout.addLayout(layout)
        # layout.addWidget(self.pictureLabel)
        # layout.addLayout(control_box)
        # for i in range (0,10):
            
        
        # layout.addWidget(self.cntDownLabel)
        # layout.addLayout(control_box)
        
        # layout.addWidget(self.cntDownLabel)
        self.secQWidget.setLayout(vlayout)

回调函数

def onKeyPad(self):
        button=sender = self.sender()
        print("key "+button.text())
        if button.text()=="删除":
				
        elif button.text()=="确认":

        else:
            self.input.setText(self.input.text()+button.text())