给你一串序列,问你某个数在这个序列中是第几大,这个数也可能不存在
注:某些OJ可能会提示PE
#include<stdio.h>
#include<algorithm>
#include<iostream>
#include<string.h>
using namespace std;
int con[100000];
/*int minsearch(int v,int y){
int m, x = 0;
while (x < y){
m = x + (y - x) / 2;
if (con[m] == v)return m;
else if (con[m]>v)y = m;
else x = m + 1;
}
return -1;
}*/
int sbsearch(int v){
int num=0;
if (con[v] == 0)
return -1;
for (int i = 1; i < v; i++){
if (con[i] == 0)
continue;
else num += con[i];
}
return num;
}
int main(){
int n, m, t = 1;;
while (scanf_s("%d%d", &n, &m) && n&&m){
memset(con, 0, sizeof(con));
int a;
for (int i = 0; i < n; i++){
scanf_s("%d", &a);
con[a]++;
}
//sort(con, con + n);
int v;
printf("CASE# %d:\n", t++);
//for (int i = 1; i <= n; i++)
//cout << i<<" "<<con[i] << endl;
for (int i = 0; i < m; i++){
int v;
scanf_s("%d", &v);
if (sbsearch(v)==-1)
cout << v << " not found" << endl;
else
cout << v << " found at " << sbsearch(v)+1 << endl;
}
}
return 0;
}