public static void main(String[] args) { int max = 0; int[] count = new int[255]; char ch; String input = "QEQSERTWR145657ABCsfgsdEYP[YLYULYfgDEFsdgfsgtutjtyktEDYERTYEEAERYTEYERALUILYUILO"; for(int i = 0; i < input.length(); i++) { int cou = ++count[(int)input.charAt(i)]; if(cou >= max) { max = cou; ch = input.charAt(i); } } for(int i=0;i<count.length;i++){ if(count[i]==0) continue; System.out.println(String.valueOf((char)i)+" "+count[i]); } }
JAVA 高效判断字符串的字符个数
最新推荐文章于 2022-11-07 22:29:24 发布