How will you print numbers from 1 to 100 without using loop?

zhaoquanguo

于 2011-06-15 08:49:00 发布

阅读量410

点赞数

分类专栏： C++ 文章标签： numbers recursion

C++ 专栏收录该内容

8 篇文章

订阅专栏

本文介绍了一个使用递归方法打印从1到指定数字的C语言程序示例。递归是一种替代循环的方法，通过函数自身调用实现重复操作。该程序演示了如何通过递归方式打印一系列数字，并分析了其时间复杂度。

Here is a solution that prints numbers using recursion.

Other alternatives for loop statements are recursion and goto statement, but use of goto is not suggestible as a general programming practice as goto statement changes the normal program execution sequence and makes it difficult to undestand and maintain.

#include <stdio.h>

/* Prints numbers from 1 to n */
void printNos(unsigned int n)
{
  if(n > 0)
  {
    printNos(n-1);
    printf("%d ",  n);
  }
  return;
}

/* Driver program to test printNos */
int main()
{
  printNos(100);
  getchar();
  return 0;
}

Time Complexity: O(n)