AWS-lambda函数中获取S3中某个文件夹下的所有文件的文件名

import boto3

def getFileNameList(bucket_name, prefix):
    s3 = boto3.resource('s3')
    bucket=bucket_name
    my_bucket = s3.Bucket(bucket)
    path_list = []
    for (bucket_name, key) in map(lambda x: (x.bucket_name, x.key), my_bucket.objects.filter(Prefix=prefix)):
        path = "s3://{}/{}".format(bucket_name, key)
        path_list.append(path)
    
    return path_list