public static <T> Predicate<T> distinctByKey(Function<? super T, Object> keyExtractor) {
Map<Object, Boolean> seen = new ConcurrentHashMap<>();
return object -> seen.putIfAbsent(keyExtractor.apply(object), Boolean.TRUE) == null;
}
List<User> users = new LinkedList<>();
users.add(new User("Jim"));
users.add(new User("Jim"));
users.add(new User("Tom"));
users.add(new User("Leo"));
List<User> distinctUsers = users.stream()
.filter(distinctByKey(User::getName))
.collect(Collectors.toList());
System.out.println(distinctUsers);//[Jim, Tom, Leo]
Java8 Lambda实现条件去重distinct List - 锐洋智能 - 博客园我们知道, Java8 lambda自带的去重为 distinct 方法, 但是只能过滤整体对象, 不能实现对象里的某个值进行判定去重, 比如: List<Integer> numbers
https://www.cnblogs.com/interdrp/p/15598689.html