Leetcode 110. Balanced Binary Tree

平衡二叉树判断算法

最新推荐文章于 2023-11-11 23:37:07 发布

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本文介绍了一种用于判断二叉树是否为高度平衡的方法。通过递归计算每个节点的左右子树深度，并确保任意节点的左右子树深度之差不超过1来实现。平衡二叉树的定义及其实现细节在文中均有详述。

Question

Given a binary tree, determine if it is height-balanced.

For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.

Code

 public int get(TreeNode root) {
        if (root == null) {
            return 0;
        }
        int ldep = get(root.left);
        if (ldep == -1) {
            return -1;
        }
        int rdep = get(root.right);
        if (rdep == -1) {
            return -1;
        }
        if (Math.abs(ldep - rdep) >= 2) {
            return -1;
        }
        return Math.max(rdep + 1, ldep + 1);

    }

    public boolean isBalanced(TreeNode root) {

        int result = get(root);
        return result != -1;
    }