JSON对象表示法是一个轻量级的基于文本的开放式标准,旨在为人类可读的数据交换。在后端开发中,越来越多的使用JSON的格式来进行数据的传递交换。那么在java语言中怎么实现json数据到java的对象的转换呢?此处我们采用jackson进行对JSON数据进行转换的。
一、准备工作,我的测试工程使用的mvn管理的。jackson的mvn依赖如下
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-core</artifactId>
<version>2.9.2</version>
</dependency>
<!-- https://mvnrepository.com/artifact/com.fasterxml.jackson.core/jackson-databind --><dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-databind</artifactId>
<version>2.9.2</version>
</dependency>
<!-- https://mvnrepository.com/artifact/com.fasterxml.jackson.core/jackson-annotations --><dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-annotations</artifactId>
<version>2.9.2</version>
</dependency>
将上述文件添加到POM文件中
二、使用ObjectMapper类来解析json数据。
1、将json格式的字符串解析为Map对象,主要适用在对JSON数据内容可能会更改的情况。示例代码如下
@Test
public void testParseJson() throws IOException {
//新建一个ObjectMapper,此类为Jackson库的主要类
ObjectMapper mapper = new ObjectMapper();
String jsonString = "{\"name\":\"Mahesh\",\"age\":21,\"birthDay\":\"1996年09月30日\"}";
System.out.println(jsonString);
//使用ObjectMapper的实例对象的readValue方法
// 来实现将Json格式的字符串解析为map
Map mapStudent = mapper.readValue(jsonString, Map.class);
String name = (String)mapStudent.get("name");
int age = (int)mapStudent.get("age");
String birthDay = (String)mapStudent.get("birthDay");
System.out.println("name:"+name + "\t age:"+ age + "\tbirthDay" + birthDay);
}
运行结果如下:
{"name":"Mahesh","age":21,"birthDay":"1996年09月30日"}name:Mahesh age:21 birthDay:1996年09月30日
2、将Json格式的字符串解析为具体的java对象
@Test
public void testParseJson2Object() throws IOException {
//新建一个ObjectMapper,此类为Jackson库的主要类
ObjectMapper mapper = new ObjectMapper();
String jsonString = "{\"name\":\"Mahesh\",\"age\":21,\"birthDay\":\"1996年09月30日\"}";
System.out.println(jsonString);
//使用ObjectMapper的实例对象的readValue方法
// 来实现将Json格式的字符串解析为Student对象
Student mapStudent = mapper.readValue(jsonString, Student.class);
System.out.println(mapStudent);
}
public class Student {
private String name;
private int age;
@JsonFormat(pattern = "yyyy年MM月dd日")
private Date birthDay;
public Student(String name, int age, Date birthDay) {
this.name = name;
this.age = age;
this.birthDay = birthDay;
}
public Student() {
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public Date getBirthDay() {
return birthDay;
}
public void setBirthDay(Date birthDay) {
this.birthDay = birthDay;
}
@Override
public String toString() {
return "Student{" +
"name='" + name + '\'' +
", age=" + age +
", birthDay=" + birthDay +
'}';
}
}
运行结果如下:
{"name":"Mahesh","age":21,"birthDay":"1996年09月30日"}
Student{name='Mahesh', age=21, birthDay=Mon Sep 30 08:00:00 CST 1996}
Student{name='Mahesh', age=21, birthDay=Mon Sep 30 08:00:00 CST 1996}
3、将java对象解析为json格式的字符串
@Test
public void testParseObject2Json() throws IOException {
Student student = new Student("李小龙",48,new Date());
//创建对象映射类
ObjectMapper mapper = new ObjectMapper();
//调用writeValueAsString方法将对象装换为json格式的字符串
String jsonStudent = mapper.writeValueAsString(student);
System.out.println(jsonStudent);
}
运行结果如下:
{"name":"李小龙","age":48,"birthDay":"2018年05月12日"}
三、使用jackson对象序列化和反序列化
@Test
public void testJsonSerializable() {
Student student = new Student();
student.setAge(20);
student.setName("Mahesh");
student.setBirthDay(new Date());
try {
writerJSON(student);
student = readJSON();
System.out.println(student);
} catch (IOException e) {
e.printStackTrace();
}
}
private void writerJSON(Student student) throws IOException {
ObjectMapper mapper = new ObjectMapper();
mapper.writeValue(new File("student.json"), student);
}
private Student readJSON() throws IOException {
ObjectMapper mapper = new ObjectMapper();
Student student = mapper.readValue(new File("student.json"), Student.class);
return student;
}
使用writerJSON方法将student对象序列到文件student.json中。
使用readJSON方法将student.json文件中json数据绑定到student对象中。