题目地址:Defanging an IP Address - LeetCode
Given a valid (IPv4) IP address, return a defanged version of that IP address.
A defanged IP address replaces every period “.” with “[.]”.
Example 1:
Input: address = "1.1.1.1"
Output: "1[.]1[.]1[.]1"
Example 2:
Input: address = "255.100.50.0"
Output: "255[.]100[.]50[.]0"
Constraints:
The given address is a valid IPv4 address.
这道题目很简单,很水。
Python解法如下:
class Solution:
def defangIPaddr(self, address: str) -> str:
return address.replace('.','[.]')
C++解法如下:
class Solution {
public:
string defangIPaddr(string address) {
return regex_replace(address, regex("[.]"), "[.]");
}
};

该博客介绍了如何解决LeetCode上的第1108题——将有效的IPv4地址转化为防御版本。防御版IP地址将每个点"."替换为"[.]"。文章提供了Python和C++两种解题方案。
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