Given an array with n objects colored red, white or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note: You are not suppose to use the library’s sort function for this problem.
Example:
Input: [2,0,2,1,1,0]
Output: [0,0,1,1,2,2]
Follow up:
- A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0’s, 1’s, and 2’s, then overwrite array with total number of 0’s, then 1’s and followed by 2’s. - Could you come up with a one-pass algorithm using only constant space?
这道题目很简单,就是排序
Python解法如下:
class Solution:
def sortColors(self, nums: List[int]) -> None:
"""
Do not return anything, modify nums in-place instead.
"""
if nums==[]:
return
a = [0, 0, 0]
j = 0
for i in nums:
a[i] += 1
for i in range(0, len(nums)):
while a[j] <= 0:
j += 1
nums[i] = j
a[j] -= 1
太简单了,其他解法就不写了。

该博客介绍了如何用Python解决LeetCode上的75题——Sort Colors,要求将数组中的红、白、蓝三种颜色的元素按顺序进行原地排序。文章提到了一种双遍历的计数排序方法,并询问是否能设计出仅使用常量空间的一次遍历算法。在博客内容中给出了简单的Python解法。
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