LeetCode374 Guess Number Higher or Lower

博客围绕LeetCode上的猜数字游戏题目展开。题目要求从1到n中猜出所选数字,每次猜错会告知高低。给出了示例及解题代码,通过二分查找算法,不断缩小猜测范围,最终找到目标数字。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

题目:

       We are playing the Guess Game. The game is as follows:

       I pick a number from 1 to n. You have to guess which number I picked.Every time you guess wrong, I'll tell you whether the number is higher or lower.You call a pre-defined API guess(int num) which returns 3 possible results (-1, 1, or 0):

       -1 : My number is lower

       1 : My number is higher

       0 : Congrats! You got it!

       Example :

              Input: n = 10, pick = 6

              Output: 6

/* The guess API is defined in the parent class GuessGame.
   @param num, your guess
   @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
      int guess(int num); */

public class Solution extends GuessGame {
    public int guessNumber(int n) {
        int l = 0; 
        int r = n;
        
        while(true){
            int mid = l + (r - l >> 1);
            if(guess(mid) == 0)
                return mid;
            else if(guess(mid) == -1)
                r = mid - 1;
            else 
                l = mid + 1;
        }
    }
}

 

 

 

 

 

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值