codeforces 545A Toy Cars

本文介绍了一个简单的编程问题,即通过给定的碰撞矩阵确定哪些玩具车在比赛中未被翻转过,即为“好”车,并输出这些车的编号。

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A. Toy Cars
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

Little Susie, thanks to her older brother, likes to play with cars. Today she decided to set up a tournament between them. The process of a tournament is described in the next paragraph.

There are n toy cars. Each pair collides. The result of a collision can be one of the following: no car turned over, one car turned over, both cars turned over. A car is good if it turned over in no collision. The results of the collisions are determined by an n × n matrix А: there is a number on the intersection of the і-th row and j-th column that describes the result of the collision of the і-th and the j-th car:

  •  - 1: if this pair of cars never collided.  - 1 occurs only on the main diagonal of the matrix.
  • 0: if no car turned over during the collision.
  • 1: if only the i-th car turned over during the collision.
  • 2: if only the j-th car turned over during the collision.
  • 3: if both cars turned over during the collision.

Susie wants to find all the good cars. She quickly determined which cars are good. Can you cope with the task?

Input

The first line contains integer n (1 ≤ n ≤ 100) — the number of cars.

Each of the next n lines contains n space-separated integers that determine matrix A.

It is guaranteed that on the main diagonal there are  - 1, and  - 1 doesn't appear anywhere else in the matrix.

It is guaranteed that the input is correct, that is, if Aij = 1, then Aji = 2, if Aij = 3, then Aji = 3, and if Aij = 0, then Aji = 0.

Output

Print the number of good cars and in the next line print their space-separated indices in the increasing order.

Examples
input
Copy
3
-1 0 0
0 -1 1
0 2 -1
output
Copy
2
1 3 
input
Copy
4
-1 3 3 3
3 -1 3 3
3 3 -1 3
3 3 3 -1
output
Copy
0

水题:就是题意刚开始看的不明白

#include<bits/stdc++.h>  
using namespace std;  
typedef long long ll;  
const int inf = 0x3f3f3f3f;  
int main()   
{  
    // freopen("in.txt","r",stdin);
    int n;
    int s[110][110];
    int ans=0;
    cin>>n;
    for(int i=1;i<=n;i++)
    {
    	for(int j=1;j<=n;j++)
    	{
    		cin>>s[i][j];
    	}
    }
    int a[110];
    memset(a,1,sizeof(a));
    for(int i=1;i<=n;i++)
    {
    	for(int j=1;j<i;j++)
    	{
    		if(s[i][j]==1)
    		{
    			a[i]=0;
    		}
    		else if(s[i][j]==2)
    		{
    			a[j]=0;
    		}
    		else if(s[i][j]==3)
    		{
    			a[i]=0;
    			a[j]=0;
    		}
    	}
    }
    for(int i=1;i<=n;i++)
    {
    	if(a[i])
    		ans++;
    }
    if(ans==0)
    	printf("0\n");
    else
    {
    	printf("%d\n",ans);
    	for(int i=1;i<=n;i++)
    	{
    		if(a[i])
    		{
                 printf("%d ",i);
            }
    	}
    	printf("\n");
    }
    return 0;  
}


### 关于 Codeforces Problem 1804A 的解决方案 Codeforces 是一个广受欢迎的在线编程竞赛平台,其中问 1804A 可能涉及特定算法或数据结构的应用。尽管未提供具体目描述,但通常可以通过分析输入输出样例以及常见解法来推导其核心逻辑。 #### 目概述 假设该问是关于字符串处理、数组操作或其他基础算法领域的内容,则可以采用以下方法解决[^2]: 对于某些初学者来说,遇到不熟悉的语言(如 Fortran),可能会感到困惑。然而,在现代竞赛环境中,大多数情况下会使用更常见的语言(C++、Python 或 Java)。因此,如果目提及某种神秘的语言,可能只是为了增加趣味性而非实际需求。 #### 解决方案思路 以下是基于一般情况下的潜在解答方式之一: ```cpp #include <bits/stdc++.h> using namespace std; int main(){ int t; cin >> t; // 输入测试用例数量 while(t--){ string s; cin >> s; // 获取每组测试数据 // 假设这里需要执行一些简单的变换或者判断条件... bool flag = true; // 初始化标志位为真 for(char c : s){ if(c != 'a' && c != 'b'){ flag = false; break; } } cout << (flag ? "YES" : "NO") << "\n"; // 输出结果 } return 0; } ``` 上述代码片段展示了一个基本框架,适用于许多入门级字符串验证类问。当然,这仅作为示范用途;真实场景下需依据具体要求调整实现细节。 #### 进一步探讨方向 除了官方解外,社区论坛也是获取灵感的好地方。通过阅读他人分享的经验教训,能够加深对该类型习的理解程度。同时注意积累常用技巧并灵活运用到不同场合之中[^1]。
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