codeforces 501A Contest

最新推荐文章于 2023-02-17 16:02:43 发布

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最新推荐文章于 2023-02-17 16:02:43 发布

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分类专栏： ACM算法_水题文章标签：水题

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本文介绍了一个简单的编程问题，即比较两位参赛者在Codeforces比赛中因解决不同难度的问题及提交时间差异而获得的实际分数。文章提供了完整的代码实现，用于计算并输出谁获得了更高的分数。

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Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs a points and Vasya solved the problem that costs b points. Besides, Misha submitted the problem c minutes after the contest started and Vasya submitted the problem d minutes after the contest started. As you know, on Codeforces the cost of a problem reduces as a round continues. That is, if you submit a problem that costs p points t minutes after the contest started, you get $\text{[math]}$ points.

Misha and Vasya are having an argument trying to find out who got more points. Help them to find out the truth.

Input

The first line contains four integers a, b, c, d (250 ≤ a, b ≤ 3500, 0 ≤ c, d ≤ 180).

It is guaranteed that numbers a and b are divisible by 250 (just like on any real Codeforces round).

Output

Output on a single line:

"Misha" (without the quotes), if Misha got more points than Vasya.

"Vasya" (without the quotes), if Vasya got more points than Misha.

"Tie" (without the quotes), if both of them got the same number of points.

        Examples
      
          input
        
500 1000 20 30

          output
        
Vasya

          input
        
1000 1000 1 1

          output
        
Tie

          input
        
1500 1000 176 177

          output
        
Misha

水题

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int a,b,c,d;
    cin>>a>>b>>c>>d;
    int m=max(3*a/10,a-a/250*c);
    int n=max(3*b/10,b-b/250*d);
    if(m>n)
    	printf("Misha\n");
    else if(n>m)
    	printf("Vasya\n");
    else
    	printf("Tie\n");
    return 0;
}