Description
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 ≤ n ≤ 55) — the maximum length of a number that a door-plate can hold.
Output
Output one integer — the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Sample Input
2
6
代码:
#include<stdio.h>
#include<math.h>
int main()
{
int n;
long long i,sum[100];
sum[1]=2;
for( i=2;i<=55;i++)
{
sum[i]=sum[i-1]+pow(2,i);
}
while(scanf("%d",&n)!=EOF)
{
printf("%lld\n",sum[n]);
}
return 0;
}
思路:找规律的题,开始做的时候晕了,竟然把longlong 对应的 lld 记成了ld!
规律是多一位数字(这个数字可以是7或8),所以就多了2*(上一位数)项,再加上原来的:sum[i]=sum[i-1]+pow(2,i);