【问题描述】
平面上有两个矩形A和B,其位置是任意的。编程求出其相交部分(如图中阴影部分)的面积。(0<a,b<1000)
#include <stdio.h>
#define max(x,y) (x>y?x:y)
#define min(x,y) (x<y?x:y)
#include <stdio.h>
#define max(x,y)(x>y?x:y)
#define min(x,y)(x<y?x:y)
int main()
{
double x1,x2,y1,y2,x3,x4,y3,y4;
double a,b,c,d;
scanf("%lf %lf %lf %lf\n",&x1,&y1,&x2,&y2);
scanf("%lf %lf %dlf %lf\n",&x3,&y3,&x4,&y4);
a=min(max(x1,x2),max(x3,x4));
b=min(max(y1,y2),max(y3,y4));
c=max(min(x1,x2),min(x3,x4));
d=max(min(y1,y2),min(y3,y4));
if ( a>c && b>d )
printf("%lf\n",(a-c)*(b-d));
else
printf("0");
return 0;
}
注意:考虑要周全