UIWebView响应Touch事件的方法(不用Private API, iOS4 Tested)
UIWebView响应不了Touch事件,很久以前就很难解决。最后有一个叫做UICWebView的东西,虽然用了private api,但是可以用。不过----UICWebView或者任何用UIWebDocumentView获得事件的方法在iOS4 100%会出错(因为UIWebDocumentView这个东西没了)。用下面的方法可以让UIWebView响应Touch事件,而且不会影响滚动拖拽的bouncing。如果需要touch的个数或者坐标,也很简单,不过需要自己修改代码里的JavaScript。
- (void)viewDidLoad {
[super viewDidLoad];
self.webView.delegate=self;
NSString *resourcePath = [ [NSBundle mainBundle] resourcePath];
NSString *filePath = [resourcePath stringByAppendingPathComponent:@"test.html"];
NSString *htmlstring=[[NSString alloc] initWithContentsOfFile:filePath encoding:NSUTF8StringEncoding error:nil];
NSString *newHTMLString=[htmlstring stringByAppendingString:@"<script language=\"javascript\">document.ontouchstart=function(){ document.location=\"myweb:touch:start\"; }; document.ontouchend=function(){ document.location=\"myweb:touch:end\"; }; document.ontouchmove=function(){ document.location=\"myweb:touch:move\"; } </script>"];
[self.webView loadHTMLString:newHTMLString baseURL:[NSURL fileURLWithPath:[[NSBundle mainBundle] bundlePath]]];
[htmlstring release];
}
- (BOOL)webView:(UIWebView*)webView shouldStartLoadWithRequest:(NSURLRequest*)request navigationType:(UIWebViewNavigationType)navigationType {
NSString *requestString = [[request URL] absoluteString];
NSArray *components = [requestString componentsSeparatedByString:@":"];
if ([components count] > 1 && [(NSString *)[components objectAtIndex:0] isEqualToString:@"myweb"]) {
if([(NSString *)[components objectAtIndex:1] isEqualToString:@"touch"])
{
NSLog(@"%@",[components objectAtIndex:2]);
}
return NO;
}
return YES;
}
上面说到要做翻书效果,不要这么麻烦
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函数里处理即可,sdk>3.2里的特性,最近刚好做了个,苹果做的这个手势判断器挺好的