leetcode-341-Flatten Nested List Iterator

本文探讨了如何使用类似于深度优先搜索的迭代方式来遍历原始数据结构,重点在于如何定义hasNext()和next()函数,确保在遇到整数时返回正确结果,并在hasNext()中维护堆栈顶元素始终为整数的迭代器。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

Error:
Too many error, I think it is I cannot define the function too well.

The problem is not let you reconstruct the data struct the flatten, it is a iterator to iterate the origin data structure, so it need to get the result on the fly!

So it is like a iterate like DFS, when meet a list, push it on the stack, and record its begin iterator and end iterator at the same time. When begin == end, pop it

Note:

  1. define hasNext() as the function that when meet the integer then return true, not check if current stack has element.
  2. define next() just call hasNext(), then return the integer of top element, since in hasNext() we make sure the top iterator always is integer.
评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值