taku

 问题描述 """ id counts 0 001 12 1 002 3 2 001 4 按对应id整理整理成如下格式 id 001 16 002 3 """ python实现： import pandas as pd df = pd.DataFrame({'id': ['001', '002', '001'], ...

''' 统计词频 ''' def count_words(l): dic = {} for word in l: if word not in dic: dic[word] = 1 else: dic[word] += 1 return dic if __name__ == '__ma...