Android开发 之 EditText 输入金额 float类型

EditText 输入金额 float类型

1.xml中，属性 inputtype 

   <EditText
            android:id="@+id/et_jine"
            android:layout_width="match_parent"
            android:layout_height="40dp"
            android:hint="请输入金额"
            android:layout_alignBottom="@+id/tv_Y"
            android:layout_toRightOf="@+id/tv_Y"
            android:layout_marginRight="50dp"
            android:layout_marginBottom="10dp"
            android:paddingLeft="15dp"
            android:background="@drawable/shape_rechange"
            android:inputType="numberDecimal"
            />

2. 监听edittext的输入内容的变化

    private void initdata() {
        et_jine.addTextChangedListener(new TextChange());
    }

    public class TextChange implements TextWatcher
    {
        @Override
        public void beforeTextChanged(CharSequence s, int start, int count, int after) {

        }
        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {

        }
        @Override
        public void afterTextChanged(Editable s) {
            int selectionStart = et_jine.getSelectionStart();
            int selectionEnd = et_jine.getSelectionEnd();
            if (!isOnlyPointNumber(s.toString()) && s.length() > 0) {
                //删除多余输入的字（不会显示出来）
                s.delete(selectionStart - 1, selectionEnd);
                et_jine.setText(s);
                et_jine.setSelection(s.length());
            }
        }
    }

    public  boolean isOnlyPointNumber(String number) {
        Pattern pattern = Pattern.compile("^\\d+\\.?\\d{0,1}$");
        Matcher matcher = pattern.matcher(number);
        return matcher.matches();
    }

3. 上面代码中通过正则表达式判断

保留一位小数  ，保留两位的话把1变成2；

"^\\d+\\.?\\d{0,1}$"