POJ-1008-Maya Calendar

一个模拟题，要求对日历进行转换

代码：

#include<cstdio>
#include<cstring>
#include<iostream>
#include<string>
using namespace std;
string m1[19]={"pop","no", "zip", "zotz", "tzec", "xul", "yoxkin", "mol", "chen", "yax", "zac", "ceh", "mac", "kankin", "muan", "pax", "koyab", "cumhu","uayet"};
string m2[20]={"imix", "ik", "akbal", "kan", "chicchan", "cimi", "manik", "lamat", "muluk", "ok", "chuen", "eb", "ben", "ix", "mem", "cib", "caban", "eznab", "canac", "ahau"};
int main()
{
    int n;
    while(scanf("%d",&n)!=EOF)
    {
	printf("%d\n",n);
	int year,day;
	char ch;
	string mm;
	for(int i=0;i<n;i++)
	{
	    cin>>day>>ch>>mm>>year;
	    int index;
	    for(int i=0;i<19;i++)
		if(mm==m1[i])
		{
		    index=i;
		    break;
		}
	    int sum=year*365+index*20+day;
	    int ansyear=sum/260;
	    int ita=sum%20;
	    int itb=sum%13+1;
	    string ansmm=m2[ita];
	    int ansday=itb;
	    cout<<ansday<<' '<<ansmm<<' '<<ansyear<<endl;
	}
    }
    return 0;
}