JS 获取url传递参数

方法一：

function getrequest() {
            var url = location.search; //获取url中"?"符后的字串

            if (url != null && url != "") {
                var therequest = new Object();
                if (url.indexOf("?") != -1) {
                    var str = url.substr(1);
                    strs = str.split("&");
                    for (var i = 0; i < strs.length; i++) {
                        therequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]);
                    }
                }
                return therequest;
            }
            else {
                return "";
            }
        }

        var request = new Object();
        request = getrequest();

        if (request != null && request != "") { document.title = request["windowName"]; }

方法二：

(function ($) {
                $.getUrlParam = function (name) {
                    var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)");
                    var r = window.location.search.substr(1).match(reg);
                    if (r != null) return unescape(r[2]); return null;
                }
            })(jQuery);


            var OpenID = $.getUrlParam('popenid');