#include<stdio.h>
int pow(int i) {
int j, k=1;
for (j = 0; j <i; j++) {
k *= 10;
}
return k;
}
int main(void) {
int da, na,db, nb, m;
long int a, b;
na = nb = 0;
m = -1;
scanf("%ld %d %ld %d", &a, &da, &b, &db);
while (a != 0) {
if (a % 10 == da) {
m++;
na+=pow(m)*da;
}
a/=10;
}
m = -1;
while (b != 0) {
if (b % 10 == db) {
m++;
nb+=pow(m)*db;
}
b/=10;
}
printf("%d", na + nb);
return 0;
}
1016 部分A+B
最新推荐文章于 2025-04-14 10:00:03 发布