https://leetcode.cn/problems/binary-search/
思路
所有元素有序是不重复的,二分法
code
class Solution {
public:
int search(vector<int>& nums, int target) {
int lens = nums.size();
int left = 0;
int right = lens -1;
if(nums[right]<target||nums[left]>target) return -1;
while(left<=right){
int mid= (left+right)/2;
if(nums[mid]==target) return mid;
else if(nums[mid]<target) left=mid+1;
else if(nums[mid]>target) right=mid-1;
}
return -1;
}
};