题目1010：A + B

Problem:

Solution:

这道题的关键是要搞清楚题目中所蕴含的逻辑关系和运行顺序，没有什么有含金量的算法，具体详情看代码，需要注意的是两个加数的计算部分，由于输入即可以形如“six”也可以为“zero six”也可为“five six”，因此如何准确的根据输入情况得到加数就比较关键了

#include <iostream>
#include <string>


using namespace std;

string sto[10] = {"zero","one","two","three","four","five","six","seven","eight","nine"};
int converse(string m)
{
    int i;
    for (i = 0;i < 10;i++)
    {
        if(sto[i] == m) return i;
    }
    return -1;
}

int main()
{
    string m;
    bool flag = true;
    int first = 0,second = 0;
    while (cin >> m)
    {
        int t = converse(m);
        if (t != -1 && flag)
        {
            first *= 10;
            first += t;
        }
        else if(t != -1 && !flag)
        {
            second *= 10;
            second += t;
        }
        else if (t == -1 && m == "+")
        {
            flag = false;
        }
        else if (t == -1 && m == "=")
        {
            if (first == 0 && second == 0) break;
            cout << first+second << endl;
            flag = true;
            first = 0;
            second = 0;
        }
    }
    return 0;
}