http://codevs.cn/problem/1220/
三角形从顶端往下走找一个值最大的路线。
很自然的想到,下一点的值等于上一层相连两点较大的点。
#include<iostream>
#include<stdio.h>
#include<algorithm>
using namespace std;
int max(int a, int b)
{
if (a>b)
return a;
else
return b;
}
int main()
{
int n = 0;
int ditu[102][102] = { 0 };
int shuzi[102][102] = { 0 };
cin >> n;
for (int i = 1; i <=n; i++)
{
for (int j = 1; j <= i; j++)
scanf("%d",&ditu[i][j]);
}
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= i; j++)
shuzi[i][j] = ditu[i][j] + max(shuzi[i-1][j-1],shuzi[i-1][j]);
}
int max = -111111;
for (int i = 1; i <= n;i++)
if (max < shuzi[n][i])
max = shuzi[n][i];
cout << max << endl;
return 0;
}