XiaoenLee的博客

个人代码库，方便后期CV，不喜勿喷

y=x^3-5*x^2+6

𝑦=𝑥^3−5𝑥^2+6

目录一、方程二、原理图三、代码四、运行结果一、方程非线性方程:f(x)=x^3-x-1对应迭代法方程：x=𝑥−(𝑥^3−𝑥−1)/(3𝑥^2−1)；（其中一种）二、原理图三、代码#include <stdio.h>#include <math.h>//x^3-x-1=0//对应迭代式x=x-(x^3-x-1)/(3*x^2-1)double functions(double...

题目：流程图：代码：#include <stdio.h>#include <math.h>//y=sinX-X^2/4//区间(1.5，2) 误差10^(-2)// (2-1.5)/2^(k+1)<=1/100double functions(double x){ return (sin(x)-x*x/4);}int main(){ int k,K; double a; double b;..

#include<stdlib.h>#include "math.h"#include "stdio.h"#define PI 3.1415926535//cos(xita1)*x1+cos(xita2)*x2+cos(xita3)*x3=0//cos(xita4)*x1+cos(xita5)*x2+cos(xita6)*x3=0//cos(xita7)*x1+cos(xita8)*x2+cos(xita9)*x3=0/*输入：3 3xita1 xita2 xita3.....