#include <set>
#include <map>
#include <ctime>
#include <queue>
#include <cmath>
#include <stack>
#include <limits>
#include <vector>
#include <bitset>
#include <string>
#include <cstdio>
#include <cstring>
#include <fstream>
#include <string.h>
#include <iostream>
#include <algorithm>
#define LL long long
#define Vi vector<int>
#define Si set<int>
#define readf freopen("input.txt","r",stdin)
#define writef freopen("output.txt","w",stdout)
#define FF(i,a) for(int i(0); i < (a); i++)
#define FD(i,a) for(int i(a); i >= (1); i--)
#define FOR(i,a,b) for(int i(a);i <= (b); i++)
#define FOD(i,a,b) for(int i(a);i >= (b); i--)
#define PD(a) printf("%d\n",a)
#define SET(a,b) memset(a,b,sizeof(a))
#define SD(a) scanf("%d",&(a))
#define LN printf("\n")
#define PS printf(" ")
#define pb push_back
#define lson l , m , rt << 1
#define rson m + 1 , r , rt << 1 | 1
const double pi = acos(-1.0);
const int maxn = 301;
const int INF = 99999999;
const int dx[]={0,1,0,-1};
const int dy[]={1,0,-1,0};
using namespace std;
int N,tmp;
int sum[maxn],f[maxn][maxn];
int dp(int l,int r)
{
int i,ans,t;
if (f[l][r]>=0) return f[l][r];
ans=0x7fffffff;
FOR(i,l,r-1)
{
t=dp(l,i)+dp(i+1,r)+sum[r]-sum[l-1];
if (ans>t) ans=t;
}
f[l][r]=ans;
return f[l][r];
}
int main(){
SD(N);
FOR(i,1,N){
SD(tmp);
sum[i]=sum[i-1]+tmp;
//printf("sum[%d]=%d\n",i,sum[i]);
f[i][i]=0; //自己和自己合并当然合并值为0;
}
FOR(i,1,N) FOR(j,i+1,N) f[i][j]=-1;
dp(1,N);
printf("%d\n",f[1][N]);
return 0;
}
tyvj 1055 沙子合并
最新推荐文章于 2023-07-27 10:08:33 发布