C++的class回调

C++对象的成员函数作为回调的方法：https://blog.youkuaiyun.com/this_capslock/article/details/17001003

https://blog.youkuaiyun.com/SweetTool/article/details/72811638

问题：不允许对不可访问的基类进行转换

下面的代码会出现不可转换的问题

class IIDMClientCallback {
 public:
  virtual void onServiceFound(const IDMServiceInfo& service_info) {}
  virtual void OnResponse(int request_id, const char* buf, int buf_len) {}
};

class MyIIDMClientCallback : IIDMClientCallback
{
public:
  MyIIDMClientCallback() {};
  void onServiceFound(const IDMServiceInfo& service_info) {
    
  }

  void OnResponse(int request_id, const char* buf, int buf_len) {
    
  }
};

使用
  MyIIDMClientCallback * myIIDMClientCallback = new MyIIDMClientCallback();
  idmClientApiTmp->RegisterIDM(myIIDMClientCallback);

解决：发现继承的时候没有加public继承