An easy problem
Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3896 Accepted Submission(s): 2729
Problem Description
In this problem you need to make a multiply table of N * N ,just like the sample out. The element in the i
th row and j
th column should be the product(乘积) of i and j.
Input
The first line of input is an integer C which indicate the number of test cases.
Then C test cases follow.Each test case contains an integer N (1<=N<=9) in a line which mentioned above.
Then C test cases follow.Each test case contains an integer N (1<=N<=9) in a line which mentioned above.
Output
For each test case, print out the multiply table.
Sample Input
2 1 4
Sample Output
1 1 2 3 4 2 4 6 8 3 6 9 12 4 8 12 16HintThere is no blank space at the end of each line.
Author
XHD
Source
Recommend
威士忌
//一行最后一个则输出换行,否则输出空格。
#include<stdio.h>
int main()
{
int c, n, i, j;
scanf("%d", &c);
while(c--)
{
scanf("%d", &n);
for(i = 1; i <= n; i++)
for(j = 1; j <= n; j++)
{
printf("%d", i*j);
if(j == n)
printf("\n");
else
printf(" ");
}
}
return 0;
}
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