How many days?
Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3358 Accepted Submission(s): 1998
Problem Description
8600的手机每天消费1元,每消费K元就可以获赠1元,一开始8600有M元,问最多可以用多少天?
Input
输入包括多个测试实例.每个测试实例包括2个整数M, k,(2 <= k <= M <= 1000).M = 0, k = 0代表输入结束.
Output
对于每个测试实例输出一个整数,表示M元可以用的天数。
Sample Input
2 2 4 3 0 0
Sample Output
3 5
Author
8600
Source
Recommend
LL
#include "stdio.h"
int main()
{
int m, k, num, t;
while(~scanf("%d%d", &m, &k), m||k)
{
num = 0;
t = m;
while (t / k)
{
num += t / k;
t = t / k + t % k;
}
printf("%d\n", m + num);
}
return 0;
}