Rightmost Digit
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 21027 Accepted Submission(s): 8068
Problem Description
Given a positive integer N, you should output the most right digit of N^N.
Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single positive integer N(1<=N<=1,000,000,000).
Each test case contains a single positive integer N(1<=N<=1,000,000,000).
Output
For each test case, you should output the rightmost digit of N^N.
Sample Input
2 3 4
Sample Output
7 6HintIn the first case, 3 * 3 * 3 = 27, so the rightmost digit is 7. In the second case, 4 * 4 * 4 * 4 = 256, so the rightmost digit is 6.
Author
Ignatius.L
#include <iostream>
using namespace std;
int main()
{
int j, k, l, n;
cin>>k;
while (k--)
{
cin>>n;
j = n%4;
n = n%10;
l = 1;
switch(j) {
case 1: l = n%10;
break;
case 2: l = n*n%10;
break;
case 3: l = n*n*n%10;
break;
case 0: l = n*n*n*n%10;
break;
default:
break;
}
cout<<l<<endl;
}
return 0;
}
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